Theodolite Target
November 15th, 2005
Surveying question?
For the purpose of determining the distance between two points, a theodolite was set up at one point and a subtense bar 2m long between its targets was supported in the proper position at the the other point.If the measured angle between the targets on the bar was 3 degrees 37 min 30 sec, the horizontal distance between the two points was…? i got 103.68 ft?
While I wonder why you are mixing meters and feet, if you need the answer in feet, it looks to me like you got it right.
[EDIT] since you got the same answer, I assume you used the same method, but I used (2m / 2) / tan(3°37’30″ / 2) = 31.6m, then used the conversion function in my calculator to convert to meters to feet
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Hubbs Theodolite and Photogrammetry Targets $22.50 |
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Hubbs Theodolite and Photogrammetry Targets $22.50 |
